Difference between revisions of "2012 UNCO Math Contest II Problems/Problem 6"

(Solution)
(Solution: MAJOR CHANGE)
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== Solution ==
 
== Solution ==
<math>210</math>
+
<math>180%
 +
 
 +
600 = 2^3 * 3 * 5^2
 +
 
 +
let make possible pairs so :
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2 of the digits has to be 5,5
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3 digits are left with 2^3 *3 so pairs are :
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(8,1,3),(4,2,3),(6,4,1)
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ANSWER IS </math> 5! /2!  $ *3 = 180
  
 
== See Also ==
 
== See Also ==

Revision as of 13:27, 26 August 2025

Problem

How many $5$-digit positive integers have the property that the product of their digits is $600$?


Solution

$180%

600 = 2^3 * 3 * 5^2

let make possible pairs so :

2 of the digits has to be 5,5 3 digits are left with 2^3 *3 so pairs are : (8,1,3),(4,2,3),(6,4,1) ANSWER IS$ (Error compiling LaTeX. Unknown error_msg) 5! /2! $ *3 = 180

See Also

2012 UNCO Math Contest II (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10
All UNCO Math Contest Problems and Solutions