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Difference between revisions of "2019 Mock AMC 10B Problems/Problem 1"
 
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==Problem==
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What is the difference between <math>6+7+8+9+10</math> and <math>1+2+3+4+5</math>?
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<math>\textbf{(A)}\ 10\qquad\textbf{(B)}\ 15\qquad\textbf{(C)}\ 20\qquad\textbf{(D)}\ 25\qquad\textbf{(E)}\ 30</math>
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==Solution==
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Simply computing we get: <cmath>40-15</cmath> which equals <cmath></cmath> <math>\boxed{\bold{D}}</math> <math>\bold{25}</math>
 
Simply computing we get: <cmath>40-15</cmath> which equals <cmath></cmath> <math>\boxed{\bold{D}}</math> <math>\bold{25}</math>

Latest revision as of 13:29, 21 September 2025

Problem

What is the difference between $6+7+8+9+10$ and $1+2+3+4+5$?

$\textbf{(A)}\ 10\qquad\textbf{(B)}\ 15\qquad\textbf{(C)}\ 20\qquad\textbf{(D)}\ 25\qquad\textbf{(E)}\ 30$

Solution

Simply computing we get: \[40-15\] which equals \[\] $\boxed{\bold{D}}$ $\bold{25}$

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