Difference between revisions of "FOIL"
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<cmath>(a+b)(c+d) = ac + ad + bc + bd</cmath> | <cmath>(a+b)(c+d) = ac + ad + bc + bd</cmath> | ||
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| + | Here are a few examples. | ||
| + | |||
| + | <cmath>(5x + 3)(2x - 6)</cmath> | ||
| + | |||
| + | First we multiply the first terms, <cmath>5x</cmath> and <cmath>2x</cmath>, yielding <cmath>10x^2</cmath>. | ||
| + | |||
| + | Then, the outside terms, <cmath>5x</cmath> and <cmath>-6</cmath>, giving us <cmath>-30x</cmath>. | ||
| + | |||
| + | Next, the inside terms, <cmath>3</cmath> and <cmath>2x</cmath>, which is <cmath>6x</cmath>. | ||
| + | |||
| + | Finally, we multiply the last terms, <cmath>-6</cmath> and <cmath>3</cmath>, which is <cmath>-18</cmath>. | ||
| + | |||
| + | Thus, our answer is <cmath>10x^2 - 30x + 6x - 18</cmath>, which, when simplified, gives us a final answer of <cmath>\boxed{10x^2 - 24x - 18}</cmath>. | ||
== See also == | == See also == | ||
Revision as of 11:00, 16 August 2008
FOIL, standing for first, outside, inside, last, is a mnemonic device for remembering the distributive property when two binomials are multiplied.
Here are a few examples.
First we multiply the first terms,
and
, yielding
.
Then, the outside terms,
and
, giving us
.
Next, the inside terms,
and
, which is
.
Finally, we multiply the last terms,
and
, which is
.
Thus, our answer is
, which, when simplified, gives us a final answer of
.
See also
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