Difference between revisions of "2008 Grade 8 CEMC Gauss Problems/Problem 1"

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-==Problem==
+{{delete|moved}}
-The value of <math>8 \times (6 - 4) + 2</math> is
-<math> \text{ (A) }\ 46 \qquad\text{ (B) }\ 20 \qquad\text{ (C) }\ 18 \qquad\text{ (D) }\ 12 \qquad\text{ (E) }\ 56 </math>
-==Solution 1==
-We can use order of operations to evaluate the expression:
-<math>8 \times (6 - 4) + 2 = 8 \times 2 + 2 = \boxed {\textbf {(C) } 18}</math>
-~anabel.disher
-==Solution 2==
-We can subtract <math>2</math> from each answer choice, and see if the result is divisible by <math>8</math> (which works because <math>2</math> plus a multiple of <math>8</math> is what we are looking for in the problem:
-<math>46 - 2 = 44</math>, which is not a multiple of <math>8</math>
-<math>20 - 2 = 18</math>, which is not a multiple of <math>8</math>
-<math>18 - 2 = 16</math>, which is a multiple of <math>8</math>
-<math>12 - 2 = 10</math>, which is not a multiple of <math>8</math>
-<math>56 - 2 = 54</math>, which is not a multiple of <math>8</math>
-The only answer choice that is <math>2</math> more than a multiple of <math>8</math> is <math>\boxed {\textbf {(C) } 18}</math>
-~anabel.disher