Difference between revisions of "2023 SSMO Accuracy Round Problems/Problem 1"

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There are <math>100</math> paragraphs, so there are <math>499</math> pauses between all lines and <math>99</math> pauses between paragraphs.
 
There are <math>100</math> paragraphs, so there are <math>499</math> pauses between all lines and <math>99</math> pauses between paragraphs.
  
Then it takes him
+
Then it takes him <cmath>23 \cdot 500 + (499 - 99) \cdot 0.5 + 99 \cdot 2 = 11898</cmath> seconds to read the entire passage.
\[
 
    23 \cdot 500 + (499 - 99) \cdot 0.5 + 99 \cdot 2 = 11898
 
\]
 
seconds to read the entire passage.
 
  
 
Then, <math>10S</math> is <math>\frac{10}{60} = \frac16</math> of this  
 
Then, <math>10S</math> is <math>\frac{10}{60} = \frac16</math> of this  
value, so <math>\lfloor 10S \rfloor = 1983</math>
+
value, so <math>\lfloor 10S \rfloor = \boxed{1983}.</math>

Revision as of 14:43, 9 September 2025

Problem

Mr. Sammy proposes a Hamburger Proclamation, which has $500$ lines, divided into paragraphs of $5$ lines each. It takes him $23$ seconds to read each line. Additionally, he adds a $0.5$ second pause between two lines in a paragraph, and a $2$ second pause between paragraphs. If it takes him $S$ minutes to read the whole Hamburger Proclamation, find $\left\lfloor 10S \right\rfloor.$

Solution

There are $100$ paragraphs, so there are $499$ pauses between all lines and $99$ pauses between paragraphs.

Then it takes him \[23 \cdot 500 + (499 - 99) \cdot 0.5 + 99 \cdot 2 = 11898\] seconds to read the entire passage.

Then, $10S$ is $\frac{10}{60} = \frac16$ of this value, so $\lfloor 10S \rfloor = \boxed{1983}.$