Difference between revisions of "2012 AMC 10B Problems/Problem 1"
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== Solution== | == Solution== | ||
In each class, there are <math>18-2=16</math> more students than rabbits. So for all classrooms, the difference between students and rabbits is <math>16 \times 4 = \boxed{\textbf{(C)}\ 64}</math> | In each class, there are <math>18-2=16</math> more students than rabbits. So for all classrooms, the difference between students and rabbits is <math>16 \times 4 = \boxed{\textbf{(C)}\ 64}</math> | ||
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Revision as of 13:14, 4 July 2013
Problem
Each third-grade classroom at Pearl Creek Elementary has 18 students and 2 pet rabbits. How many more students than rabbits are there in all 4 of the third-grade classrooms?
Solution
In each class, there are 
more students than rabbits. So for all classrooms, the difference between students and rabbits is 
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
