Difference between revisions of "2017 AMC 12A Problems/Problem 19"
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\qquad\textbf{(D)}\ \frac{37}{35} | \qquad\textbf{(D)}\ \frac{37}{35} | ||
\qquad\textbf{(E)}\ \frac{13}{12}</math> | \qquad\textbf{(E)}\ \frac{13}{12}</math> | ||
| + | |||
| + | ==See Also== | ||
| + | {{AMC12 box|year=2017|ab=A|num-b=18|num-a=20}} | ||
| + | {{MAA Notice}} | ||
Revision as of 17:21, 8 February 2017
Problem
A square with side length 
is inscribed in a right triangle with sides of length 
, 
, and 
so that one vertex of the square coincides with the right-angle vertex of the triangle. A square with side length 
is inscribed in another right triangle with sides of length , , and so that one side of the square lies on the hypotenuse of the triangle. What is 
?
See Also
| 2017 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 18 |
Followed by Problem 20 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
