Difference between revisions of "2019 Mock AMC 10B Problems/Problem 2"
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Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math> | Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math> | ||
<cmath></cmath><math>\boxed{\bold{C}}</math> | <cmath></cmath><math>\boxed{\bold{C}}</math> | ||
| − | <math>\bold{ | + | <math>\bold{15}</math> |
Revision as of 10:43, 20 January 2020
Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have 
![\[\]](http://latex.artofproblemsolving.com/5/7/f/57f1406b65f9f2e6a365b7356da731780b42cceb.png)
