Difference between revisions of "2020 AMC 12B Problems/Problem 2"
Advancedjus (talk | contribs) (→See Also) |
(→Solution) |
||
| Line 5: | Line 5: | ||
==Solution== | ==Solution== | ||
| + | Using difference of squares to factor the left term, we get | ||
| + | <cmath>\frac{100^2-7^2}{70^2-11^2} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)} = </cmath> | ||
| + | <cmath>\frac{(100-7)(100+7)}{(70-11)(70+11)} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)}</cmath> | ||
| + | Cancelling all the terms, we get <math>\boxed{\textbf{(A) 1}}</math> as the answer. | ||
==See Also== | ==See Also== | ||
Revision as of 20:23, 7 February 2020
Problem
What is the value of the following expression?
![\[\frac{100^2-7^2}{70^2-11^2} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)}\]](http://latex.artofproblemsolving.com/5/f/4/5f4f7b3d646f920fd9ef3f767aad765860768b41.png)
Solution
Using difference of squares to factor the left term, we get
![\[\frac{100^2-7^2}{70^2-11^2} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)} =\]](http://latex.artofproblemsolving.com/b/9/b/b9bfcc5c19805ee0e129d431b33d0bed28354834.png)
![\[\frac{(100-7)(100+7)}{(70-11)(70+11)} \cdot \frac{(70-11)(70+11)}{(100-7)(100+7)}\]](http://latex.artofproblemsolving.com/b/4/4/b444697a7e198c859f5a04efac8eb60127101d77.png)
Cancelling all the terms, we get 
as the answer.
See Also
| 2020 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
