Difference between revisions of "2020 AMC 8 Problems/em 1"
MRENTHUSIASM (talk | contribs) (Created page with "Since the amount of sugar is twice the amount of lemon juice, Luka uses <math>3\cdot2=6</math> cups of sugar. Since the amount of water is <math>4</math> times the amount of...") |
MRENTHUSIASM (talk | contribs) |
||
Line 1: | Line 1: | ||
+ | ==Problem== | ||
+ | Four friends do yardwork for their neighbors over the weekend, earning <math>\$15, \$20, \$25,</math> and <math>\$40,</math> respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned <math>\$40</math> give to the others? | ||
+ | |||
+ | ==Solution== | ||
Since the amount of sugar is twice the amount of lemon juice, Luka uses <math>3\cdot2=6</math> cups of sugar. | Since the amount of sugar is twice the amount of lemon juice, Luka uses <math>3\cdot2=6</math> cups of sugar. | ||
Since the amount of water is <math>4</math> times the amount of sugar, he uses <math>6\cdot4=\boxed{\text{(E) }24}</math> cups of water. | Since the amount of water is <math>4</math> times the amount of sugar, he uses <math>6\cdot4=\boxed{\text{(E) }24}</math> cups of water. | ||
+ | |||
+ | ==See also== | ||
+ | {{AMC8 box|year=2020|before = First Problem|num-a=2}} | ||
+ | {{MAA Notice}} |
Latest revision as of 10:47, 12 February 2021
Problem
Four friends do yardwork for their neighbors over the weekend, earning and
respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned
give to the others?
Solution
Since the amount of sugar is twice the amount of lemon juice, Luka uses cups of sugar.
Since the amount of water is times the amount of sugar, he uses
cups of water.
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.