Difference between revisions of "User:Jiang147369"

Revision as of 12:48, 21 April 2021

We've somehow made it here...

Credits to John Hush for the proof of $0 = 1$ and the proof of $1 = 2$

Prove: $0 = 1$

Proof:

Left side $= 0 + 0 + 0 + 0 + 0 + ...$

$= (1 - 1) + (1 - 1) + (1 - 1) + (1 - 1) + (1 - 1) + ...$

$= 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1) + ...$

$= 1$

Therefore, $0 = 1$ .

Prove: $1 = 2$

Proof:

Let $a = b$

$a^2 = ab$

$a^2 - b^2 = ab - b^2$

$(a-b)(a+b) = b(a-b)$

$a+b = b$

$b+b = b$

$2b=b$

$2=1$

Therefore, $1 = 2$ .

By the Transitive Property, $0 = 2$

Prove: $9 + 10 = 21$

$9 + 10 = 19$

$9 + 10 = 19 + 0$

$9 + 10 = 19 + 2$

Therefore, $9+10 = 21$

@@ Line 1: / Line 1: @@
 We've somehow made it here...
+== Proof of 9 + 10 = 21 ==
+Credits to [https://www.youtube.com/user/mrjohnhush/featured John Hush] for the proof of <math>0 = 1</math> and the proof of <math>1 = 2</math>
+Prove: <math>0 = 1</math>
+Proof:
+Left side <math>= 0 + 0 + 0 + 0 + 0 + ...</math>
+<math>= (1 - 1) + (1 - 1) + (1 - 1) + (1 - 1) + (1 - 1) + ...</math>
+<math>= 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1) + ...</math>
+<math>= 1</math>
+Therefore, <math>0 = 1</math>.
+Prove: <math>1 = 2</math>
+Proof:
+Let <math>a = b</math>
+<math>a^2 = ab</math>
+<math>a^2 - b^2 = ab - b^2</math>
+<math>(a-b)(a+b) = b(a-b)</math>
+<math>a+b = b</math>
+<math>b+b = b</math>
+<math>2b=b</math>
+<math>2=1</math>
+Therefore, <math>1 = 2</math>.
+By the Transitive Property, <math>0 = 2</math>
+Prove: <math>9 + 10 = 21</math>
+<math>9 + 10 = 19</math>
+<math>9 + 10 = 19 + 0</math>
+<math>9 + 10 = 19 + 2</math>
+Therefore, <math>9+10 = 21</math>