Difference between revisions of "1991 AHSME Problems/Problem 6"
MRENTHUSIASM (talk | contribs) (Made the solution much more professional and well-formatted.) |
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&= \sqrt{x^{\frac74}} \\ | &= \sqrt{x^{\frac74}} \\ | ||
&= \left(x^{\frac74}\right)^{\frac12} \\ | &= \left(x^{\frac74}\right)^{\frac12} \\ | ||
| − | &= x^{ | + | &= x^{frac78} \\ |
| − | &= \boxed{\textbf{( | + | &= \boxed{\textbf{(A) } x\sqrt{x}}. |
\end{align*}</cmath> | \end{align*}</cmath> | ||
~Hapaxoromenon (Solution) | ~Hapaxoromenon (Solution) | ||
Revision as of 17:12, 5 September 2021
Problem
If 
, then 
![$\textbf{(A) } x\sqrt{x}\qquad \textbf{(B) } x\sqrt[4]{x}\qquad \textbf{(C) } \sqrt[8]{x}\qquad \textbf{(D) } \sqrt[8]{x^3}\qquad \textbf{(E) } \sqrt[8]{x^7}$](http://latex.artofproblemsolving.com/b/c/a/bca02acf1c63a8ddb1663dd2831f63615ad8c4de.png)
Solution
Recall that square roots are one-half powers, namely 
for all 
We have
~Hapaxoromenon (Solution)
~MRENTHUSIASM (Reformatting)
See also
| 1991 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
