Difference between revisions of "2024 AIME II Problems/Problem 11"
(Created page with "loading...") |
|||
| Line 1: | Line 1: | ||
| − | + | ==Problem== | |
| + | Find the number of triples of nonnegative integers \((a,b,c)\) satisfying \(a + b + c = 300\) and | ||
| + | \begin{equation*} | ||
| + | a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000. | ||
| + | \end{equation*} | ||
| + | |||
| + | ==See also== | ||
| + | {{AIME box|year=2024|num-b=10|num-a=12|n=II}} | ||
| + | |||
| + | [[Category:]] | ||
| + | {{MAA Notice}} | ||
Revision as of 09:35, 9 February 2024
Problem
Find the number of triples of nonnegative integers \((a,b,c)\) satisfying \(a + b + c = 300\) and \begin{equation*} a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000. \end{equation*}
See also
| 2024 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 10 |
Followed by Problem 12 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
[[Category:]]
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.