Difference between revisions of "2024 AMC 10A Problems/Problem 1"
Mathkiddus (talk | contribs) (→Solution 3 (Quickest Way)) |
Mathkiddus (talk | contribs) (→Solution 3 (Quickest Way)) |
||
| Line 20: | Line 20: | ||
\end{align*}</cmath> | \end{align*}</cmath> | ||
~MRENTHUSIASM | ~MRENTHUSIASM | ||
| − | == Solution 3 ( | + | == Solution 3 (A way to get rid of some answer choices(Not recommended on the actual competition) == |
We simply look at the units digit of the problem we have(or take mod 10) | We simply look at the units digit of the problem we have(or take mod 10) | ||
<cmath>9901\cdot101-99\cdot10101 \equiv 1\cdot1 - 9\cdot1 = 2 \mod{10}.</cmath> | <cmath>9901\cdot101-99\cdot10101 \equiv 1\cdot1 - 9\cdot1 = 2 \mod{10}.</cmath> | ||
| − | Since the only answer with 2 in the units digit is <math>\boxed{\textbf{(A)}}</math> | + | Since the only answer with 2 in the units digit is <math>\textbf{(A)}</math> or <math>\textbf{(D)}</math> We can then continue if you are desperate to use guess and check or a actually valid method to find the answer is <math>\boxed{\textbf{(A)}}</math> |
~mathkiddus | ~mathkiddus | ||
Revision as of 16:30, 8 November 2024
Contents
Problem
What is the value of ![\[9901\cdot101-99\cdot10101?\]](http://latex.artofproblemsolving.com/1/3/4/134a62dd445139bc0163af4dc4a59a4de7086e6e.png)
Solution 1 (Direct Computation)
The likely fastest method will be direct computation. 
evaluates to 
and 
evaluates to 
. The difference is 
Solution by juwushu.
Solution 2 (Distributive Property)
We have
~MRENTHUSIASM
Solution 3 (A way to get rid of some answer choices(Not recommended on the actual competition)
We simply look at the units digit of the problem we have(or take mod 10)
![\[9901\cdot101-99\cdot10101 \equiv 1\cdot1 - 9\cdot1 = 2 \mod{10}.\]](http://latex.artofproblemsolving.com/c/8/e/c8ec864e059d92cfd87d3afbeeb0f6ced81dbe23.png)
Since the only answer with 2 in the units digit is 
or 
We can then continue if you are desperate to use guess and check or a actually valid method to find the answer is 
~mathkiddus
See also
| 2024 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
