Difference between revisions of "2009 Grade 8 CEMC Gauss Problems/Problem 7"
(Created page with "==Problem== The number of faces (<math>F</math>), vertices (<math>V</math>), and edges (<math>E</math>) of a polyhedron are related by the equation <math>F + V - E = 2</math>....") |
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Line 10: | Line 10: | ||
We can combine <math>6</math> and <math>8</math> to get: | We can combine <math>6</math> and <math>8</math> to get: | ||
− | <math>14 - E = 2 | + | <math>14 - E = 2</math> |
− | Adding < | + | Adding <math>E</math> to both sides, we get: |
− | < | + | <math>E + 2 = 14</math> |
− | Subtracting < | + | Subtracting <math>2</math> from both sides of the equation, we get: |
− | < | + | <math>E = \boxed {\textbf {(A) } 12}</math> |
~anabel.disher | ~anabel.disher | ||
==Solution 2== | ==Solution 2== | ||
− | We can remember that a rectangular prism has < | + | We can remember that a rectangular prism has <math>6</math> faces, <math>8</math> vertices, and <math>\boxed {\textbf {(A) } 12}</math> edges, without doing any calculation. |
~anabel.disher | ~anabel.disher |
Revision as of 22:56, 18 June 2025
Problem
The number of faces (), vertices (
), and edges (
) of a polyhedron are related by the equation
. If a polyhedron has
faces and
vertices, how many edges does it have?
Solution 1
We can use the equation provided in the problem, and plug in for
, and
for
:
We can combine and
to get:
Adding to both sides, we get:
Subtracting from both sides of the equation, we get:
~anabel.disher
Solution 2
We can remember that a rectangular prism has faces,
vertices, and
edges, without doing any calculation.
~anabel.disher