Difference between revisions of "2013 AMC 8 Problems/Problem 12"

(Solution 2)
(Solution 2)
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==Solution 2==
 
==Solution 2==
Step 1: Find the total price
+
Step 1: Find the price of each sandal
The first sandal is 50<math>. The second sandal is (1-0.4)50</math>+1/2*50<math> = </math>105
+
The first sandal is 50 dollars.
 +
The second sandal is (1-0.4)50 = 30
 +
The third sandal is 1/2*5<math> = 25
 +
Step 2: Sum them up
 +
50+30+25 = 105
 
Step 2: Divide by 150
 
Step 2: Divide by 150
<math>105/</math>150 = $21/30 = 7/10 = 70%.
+
</math>105/<math>150 = </math>21/30 = 7/10 = 70%.
 
Step 3: Subtract from 100% to find the amount he saved.
 
Step 3: Subtract from 100% to find the amount he saved.
 
100%-70% = B)30%
 
100%-70% = B)30%

Revision as of 14:46, 24 August 2025

Problem

At the 2013 Winnebago County Fair a vendor is offering a "fair special" on sandals. If you buy one pair of sandals at the regular price of $50, you get a second pair at a 40% discount, and a third pair at half the regular price. Javier took advantage of the "fair special" to buy three pairs of sandals. What percentage of the $150 regular price did he save?

$\textbf{(A)}\ 25 \qquad \textbf{(B)}\ 30 \qquad \textbf{(C)}\ 33 \qquad \textbf{(D)}\ 40 \qquad \textbf{(E)}\ 45$

Solution

First, find the amount of money one will pay for three sandals without the discount. We have $\textdollar 50\times 3 \text{ sandals} = \textdollar 150$.

Then, find the amount of money using the discount: $50 + 0.6 \times 50 + \frac{1}{2} \times 50 = \textdollar 105$.

Finding the percentage yields $\frac{105}{150} = 70 \%$.

To find the percent saved, we have $100 \% -70 \%= \boxed{\textbf{(B)}\ 30 \%}$

Solution 2

Step 1: Find the price of each sandal The first sandal is 50 dollars. The second sandal is (1-0.4)50 = 30 The third sandal is 1/2*5$= 25 Step 2: Sum them up 50+30+25 = 105 Step 2: Divide by 150$105/$150 =$21/30 = 7/10 = 70%. Step 3: Subtract from 100% to find the amount he saved. 100%-70% = B)30%


-JasonDaGoat

Video Solution

https://youtu.be/VQPKh5hc3xY ~savannahsolver

See Also

2013 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 11
Followed by
Problem 13
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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