Difference between revisions of "2013 AMC 8 Problems/Problem 12"
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The first sandal is 50 dollars. | The first sandal is 50 dollars. | ||
The second sandal is (1-0.4)50 = 30 | The second sandal is (1-0.4)50 = 30 | ||
− | The third sandal is 1/2*5 | + | The third sandal is 1/2*5$ = 25 |
Step 2: Sum them up | Step 2: Sum them up | ||
50+30+25 = 105 | 50+30+25 = 105 | ||
Step 2: Divide by 150 | Step 2: Divide by 150 | ||
− | + | 105/150 = 21/30 = 7/10 = 70 percent. | |
− | Step 3: Subtract from 100 | + | Step 3: Subtract from 100 percent to find the amount he saved. |
− | 100 | + | 100 percent -70 percent = B)30 percent |
Latest revision as of 14:47, 24 August 2025
Problem
At the 2013 Winnebago County Fair a vendor is offering a "fair special" on sandals. If you buy one pair of sandals at the regular price of $50, you get a second pair at a 40% discount, and a third pair at half the regular price. Javier took advantage of the "fair special" to buy three pairs of sandals. What percentage of the $150 regular price did he save?
Solution
First, find the amount of money one will pay for three sandals without the discount. We have .
Then, find the amount of money using the discount: .
Finding the percentage yields .
To find the percent saved, we have
Solution 2
Step 1: Find the price of each sandal The first sandal is 50 dollars. The second sandal is (1-0.4)50 = 30 The third sandal is 1/2*5$ = 25 Step 2: Sum them up 50+30+25 = 105 Step 2: Divide by 150 105/150 = 21/30 = 7/10 = 70 percent. Step 3: Subtract from 100 percent to find the amount he saved. 100 percent -70 percent = B)30 percent
-JasonDaGoat
Video Solution
https://youtu.be/VQPKh5hc3xY ~savannahsolver
See Also
2013 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.