Difference between revisions of "2024 SSMO Tiebreaker Round Problems/Problem 1"
(Created page with "==Problem== Compute the exact value of <math>2^2+0^2+2^2+4^2+20^2+22^2+24^2+40^2+42^2+202^2.</math> ==Solution==") |
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==Solution== | ==Solution== | ||
| + | We have <cmath>2^2+0^2+2^2+4^2+20^2+22^2+24^2+40^2+42^2+202^2 = </cmath><cmath>4+0+4+16+400+484+576+1600+1764+40804 = \boxed{45652}.</cmath> | ||
| + | |||
| + | ~SMO_Team | ||
Latest revision as of 14:48, 10 September 2025
Problem
Compute the exact value of 
Solution
We have ![\[2^2+0^2+2^2+4^2+20^2+22^2+24^2+40^2+42^2+202^2 =\]](http://latex.artofproblemsolving.com/5/3/9/53975c3644f72ed3d3ddb41ddaec2e76bd139ef4.png)
![\[4+0+4+16+400+484+576+1600+1764+40804 = \boxed{45652}.\]](http://latex.artofproblemsolving.com/2/d/6/2d6340452d9cb6515fcb3758bb2dc1b703d37f55.png)
~SMO_Team
