Difference between revisions of "2023 SSMO Relay Round 1 Problems/Problem 3"

 
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==Solution==
 
==Solution==
We have <math>T = 2022</math>. Let
 
<cmath>\begin{align*}
 
S = \sum_{i=0}^\infty a_i &= a_0+a_1+a_2+\sum_{i=3}^\infty a_i\\
 
&= 0+1+2022+\sum_{i=3}^\infty \left(a_{i-1}-\frac{a_{i-3}}{8}\right)\\
 
&= 2023+\sum_{i=3}^{\infty}a_{i-1}-\sum_{i=3}^\infty\frac{a_{i-3}}{8}\\
 
&= 2023+\sum_{i=2}^\infty a_i-\frac{\sum_{i=0}a_i}{8}\\
 
&= 2023+\left(\sum_{i=0}^\infty a_i-a_0-a_1\right)-\frac{S}{8}\\
 
&= 2023+(S-0-1)-\frac{S}{8}\\
 
&= 2022+\frac{7S}{8}.\\
 
\end{align*}</cmath>
 
We have
 
<cmath>\begin{align*}
 
S &= 2022+\frac{7S}{8}\implies\\
 
\frac{S}{8} &= 2022\implies\\
 
S &= 8\cdot2022 = \boxed{16176}.
 
\end{align*}</cmath>
 
 
~pinkpig
 

Latest revision as of 11:23, 15 September 2025

Problem

Let $T=TNYWR$. Find the number of solutions to the equation \[\sec^{T} (Tx) - \tan^{T}(Tx) = 1\] such $0 \le x \le \pi$

Solution