Difference between revisions of "2014 CEMC Gauss (Grade 8) Problems/Problem 10"

(Created page with "== Problem== The ratio of the number of girls to the number of boys in a class of <math>24</math> students is <math>3:5</math>. How many fewer girls than boys are in the class...")
 
 
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<math> \textbf{(A)}\ 2 \qquad\textbf{(B)}\ 4 \qquad\textbf{(C)}\ 5 \qquad\textbf{(D)}\ 6 \qquad\textbf{(E)}\ 8 </math>
 
<math> \textbf{(A)}\ 2 \qquad\textbf{(B)}\ 4 \qquad\textbf{(C)}\ 5 \qquad\textbf{(D)}\ 6 \qquad\textbf{(E)}\ 8 </math>
 
==Solution 1==
 
==Solution 1==
Let there be <math>3x</math> girls and <math>5x</math> boys in the class, as the ratio of girls to boys is <math>3:5</math>. The total is then <math>3x + 5x = 8x</math>.
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Let there be <math>3x</math> girls and <math>5x</math> boys in the class, as the ratio of girls to boys is <math>3:5</math>. The total number of students in the class is then <math>3x + 5x = 8x</math>.
  
 
We know that the class has <math>24</math> students in total. Thus, we have:
 
We know that the class has <math>24</math> students in total. Thus, we have:

Latest revision as of 14:48, 18 September 2025

Problem

The ratio of the number of girls to the number of boys in a class of $24$ students is $3:5$. How many fewer girls than boys are in the class?

$\textbf{(A)}\ 2 \qquad\textbf{(B)}\ 4 \qquad\textbf{(C)}\ 5 \qquad\textbf{(D)}\ 6 \qquad\textbf{(E)}\ 8$

Solution 1

Let there be $3x$ girls and $5x$ boys in the class, as the ratio of girls to boys is $3:5$. The total number of students in the class is then $3x + 5x = 8x$.

We know that the class has $24$ students in total. Thus, we have:

$8x = 24$

$x = 3$

There is then $5x - 3x = 2x$ fewer girls than boys, or $2 \times 3 = \boxed {\textbf {(D) } 6}$ fewer girls.

~anabel.disher