Difference between revisions of "2025 AMC 10A Problems"
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==Problem 1== | ==Problem 1== | ||
− | John has <math>6</math> mangos, Jack has <math>7</math> packs of mustard, Jill has <math>41</math> slices of bread, and Caleb has <math>300</math> tomatoes. How many complete sandwiches can they make if each sandwich takes <math>1/ | + | John has <math>6</math> mangos, Jack has <math>7</math> packs of mustard, Jill has <math>41</math> slices of bread, and Caleb has <math>300</math> tomatoes. How many complete sandwiches can they make if each sandwich takes <math>1/41</math> of a mango, <math>1/67</math> of a pack of mustard, <math>41/67</math> slices of bread, and <math>93/41</math> tomatoes? |
<math>\textbf{(A) } 10 \qquad\textbf{(B) } 20 \qquad\textbf{(C) } 67 \qquad\textbf{(D) } 41 \qquad\textbf{(E) } 93</math> | <math>\textbf{(A) } 10 \qquad\textbf{(B) } 20 \qquad\textbf{(C) } 67 \qquad\textbf{(D) } 41 \qquad\textbf{(E) } 93</math> | ||
− | [[ | + | [[2025 AMC 10A Problems/Problem 1|Solution]] |
==Problem 2== | ==Problem 2== |
Revision as of 16:04, 29 September 2025
2025 AMC 10A (Answer Key) Printable versions: • AoPS Resources • PDF | ||
Instructions
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1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 |
Contents
- 1 Problem 1
- 2 Problem 2
- 3 Problem 3
- 4 Problem 4
- 5 Problem 5
- 6 Problem 6
- 7 Problem 7
- 8 Problem 8
- 9 Problem 9
- 10 Problem 10
- 11 Problem 11
- 12 Problem 12
- 13 Problem 13
- 14 Problem 14
- 15 Problem 15
- 16 Problem 16
- 17 Problem 17
- 18 Problem 18
- 19 Problem 19
- 20 Problem 20
- 21 Problem 21
- 22 Problem 22
- 23 Problem 23
- 24 Problem 24
- 25 Problem 25
- 26 See Also
Problem 1
John has mangos, Jack has
packs of mustard, Jill has
slices of bread, and Caleb has
tomatoes. How many complete sandwiches can they make if each sandwich takes
of a mango,
of a pack of mustard,
slices of bread, and
tomatoes?
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
See Also
2025 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by 2024 AMC 10B Problems |
Followed by 2025 AMC 10B Problems | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.