Difference between revisions of "2005 iTest Problems/Problem 11"

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[[Category: Introductory Geometry Problems]]

Latest revision as of 19:09, 13 October 2025

Problem

Find the radius of the inscribed circle of a triangle with sides of length $40$, $42$, and $58$.

Solution 1

We can start by finding the area. Since $40^2+42^2=58^2$, this is a right triangle, with legs 40 and 42. By the inradius formula for a right triangle, its incircle has radius $\frac{40+42-58}{2}=\boxed{12}$.

See Also

2005 iTest (Problems, Answer Key)
Preceded by:
Problem 10
Followed by:
Problem 12
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