Difference between revisions of "2006 AMC 8 Problems/Problem 7"
(→Problem 7) |
|||
| Line 1: | Line 1: | ||
| − | == Problem 7 == | + | == Problem 7 ==( Jayesh is king ) |
| + | |||
Circle <math> X </math> has a radius of <math> \pi </math>. Circle <math> Y </math> has a circumference of <math> 8 \pi </math>. Circle <math> Z </math> has an area of <math> 9 \pi </math>. List the circles in order from smallest to the largest radius. | Circle <math> X </math> has a radius of <math> \pi </math>. Circle <math> Y </math> has a circumference of <math> 8 \pi </math>. Circle <math> Z </math> has an area of <math> 9 \pi </math>. List the circles in order from smallest to the largest radius. | ||
Revision as of 06:51, 16 October 2025
== Problem 7 ==( Jayesh is king )
Circle
has a radius of
. Circle
has a circumference of
. Circle
has an area of
. List the circles in order from smallest to the largest radius.
Solution
Using the formulas of circles,
and
, we find that circle
has a radius of
and circle
has a radius of
. Also, circle X has a radius of
. Thus, the order from smallest to largest radius is
.
Video Solution by WhyMath
See Also
| 2006 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.