Difference between revisions of "2014 CEMC Gauss (Grade 7) Problems/Problem 3"

Latest revision as of 12:54, 18 October 2025

Five times a number equals one hundred. The number is

$\textbf{(A)}\ 50\qquad\textbf{(B)}\ 10\qquad\textbf{(C)}\ 15\qquad\textbf{(D)}\ 25\qquad\textbf{(E)}\ 20$

Let $n$ be the number that we are looking for. Setting up an equation, we have:

$5n = 100$

$n = \boxed {\textbf {(E) } 20}$

To find the solution, we can start by multiply $20$ by $5$ since it is one of the middle numbers.

$20 \times 5 = 100$ , which happens to be equal to one hundred.

Thus, the answer is $\boxed {\textbf {(E) } 20}$ .

2014 CEMC Gauss (Grade 7) (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
CEMC Gauss (Grade 7)

@@ Line 13: / Line 13: @@
 To find the solution, we can start by multiply <math>20</math> by <math>5</math> since it is one of the middle numbers.
-<math>20 * 5 = 100</math>, which happens to be equal to one hundred.
+<math>20 \times 5 = 100</math>, which happens to be equal to one hundred.
 Thus, the answer is <math>\boxed {\textbf {(E) } 20}</math>.
+{{CEMC box|year=2014|competition=Gauss (Grade 7)|num-b=2|num-a=4}}