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Difference between revisions of "2012 CEMC Gauss (Grade 8) Problems/Problem 8"

 
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From these numbers, we can see that <math>0.2012</math> is between <math>\boxed{\textbf{(C) } \frac{1}{5} \text{ and } \frac{1}{4}}</math>
 
From these numbers, we can see that <math>0.2012</math> is between <math>\boxed{\textbf{(C) } \frac{1}{5} \text{ and } \frac{1}{4}}</math>
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{{CEMC box|year=2012|competition=Gauss (Grade 8)|num-b=7|num-a=9}}

Latest revision as of 20:56, 18 October 2025

Problem

The number $0.2012$ is between

$\text{ (A) }\ 0 \text{ and } \frac{1}{10} \qquad\text{ (B) }\ \frac{1}{10} \text{ and } \frac{1}{5} \qquad\text{ (C) }\ \frac{1}{5} \text{ and } \frac{1}{4} \qquad\text{ (D) }\ \frac{1}{4} \text{ and } \frac{1}{3} \qquad\text{ (E) }\ \frac{1}{3} \text{ and } \frac{1}{2}$

Solution

Converting the fractions into decimals, we have:

$\frac{1}{10} = 0.1000$

$\frac{1}{5} = 0.2000$

$\frac{1}{4} = 0.2500$

$\frac{1}{3} = 0.\overline{3333}$

$\frac{1}{2} = 0.5000$

From these numbers, we can see that $0.2012$ is between $\boxed{\textbf{(C) } \frac{1}{5} \text{ and } \frac{1}{4}}$

2012 CEMC Gauss (Grade 8) (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 8)