Difference between revisions of "2011 CEMC Gauss (Grade 7) Problems/Problem 1"

Latest revision as of 15:01, 19 October 2025

The value of $5 + 4 - 3 + 2 - 1$ is

$\textbf {(A) 0} \ \ \ \textbf {(B) 5} \ \ \ \textbf {(C) 3} \ \ \ \textbf {(D) 3} \ \ \ \textbf {(E) 7}$

$5 + 4 - 3 + 2 - 1 = 9 - 3 + 2 - 1 = 6 + 1 = \boxed {\textbf {(E) 7}}$

2011 CEMC Gauss (Grade 7) (Problems • Answer Key • Resources)
Preceded by First Problem	Followed by Problem 2
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CEMC Gauss (Grade 7)

Revision as of 09:55, 7 October 2025 (view source) Anabel.disher (talk \| contribs) (moved)		Latest revision as of 15:01, 19 October 2025 (view source) Anabel.disher (talk \| contribs)
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	<math> 5 + 4 - 3 + 2 - 1 = 9 - 3 + 2 - 1 = 6 + 1 = \boxed {\textbf {(E) 7}} </math>		<math> 5 + 4 - 3 + 2 - 1 = 9 - 3 + 2 - 1 = 6 + 1 = \boxed {\textbf {(E) 7}} </math>
		+	{{CEMC box\|year=2011\|competition=Gauss (Grade 7)\|before=First Problem\|num-a=2}}