Difference between revisions of "2013 AMC 12A Problems/Problem 4"

Revision as of 03:25, 7 February 2013

$\frac{2^{2014}+2^{2012}}{2^{2014}-2^{2012}}$

We can factor a ${2^{2012}}$ out of the numerator and denominator to obtain

$\frac{2^{2012}*(2^2+1)}{2^{2012}*(2^2-1)}$

The ${2^{2012}}$ cancels, so we get

$\frac{(2^2+1)}{(2^2-1)}=\frac{5}{3}$ , which is C

@@ Line 5: / Line 5: @@
 <math>\frac{2^{2012}*(2^2+1)}{2^{2012}*(2^2-1)}</math>
-Both the <math>{2^{2012}}</math> terms cancel, so we get
+The <math>{2^{2012}}</math> cancels, so we get
 <math>\frac{(2^2+1)}{(2^2-1)}=\frac{5}{3}</math>, which is C