Difference between revisions of "2008 AMC 12A"
(allowed) |
Michelangelo (talk | contribs) |
||
Line 27: | Line 27: | ||
**[[2008 AMC 12A Problems/Problem 24|Problem 24]] | **[[2008 AMC 12A Problems/Problem 24|Problem 24]] | ||
**[[2008 AMC 12A Problems/Problem 25|Problem 25]] | **[[2008 AMC 12A Problems/Problem 25|Problem 25]] | ||
+ | {{MAA Notice}} |
Revision as of 01:44, 30 December 2013
2008 AMC 12A problems and solutions. The first link contains the full set of test problems. The rest contain each individual problem and its solution.
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.