Difference between revisions of "2014 AMC 8 Problems/Problem 1"
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==Solution== | ==Solution== | ||
| + | We have H==8-7=1 and T=8-2+5=11. Clearly 1-11=\boxed{-10}, so our answer is <math>(A)</math>. | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2014|num-b=First Problem|num-a=2}} | {{AMC8 box|year=2014|num-b=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 19:53, 26 November 2014
Problem
Harry and Terry are each told to calculate 
. Harry gets the correct answer. Terry ignores the parentheses and calculates 
. If Harry's answer is 
and Terry's answer is 
, what is 
?
Solution
We have H==8-7=1 and T=8-2+5=11. Clearly 1-11=\boxed{-10}, so our answer is 
.
See Also
| 2014 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. 
