Difference between revisions of "1955 AHSME Problems/Problem 4"
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==Solution== | ==Solution== | ||
| − | From the equality, <math>\frac{1}{x-1}=\frac{2}{x-2}</math>, we get <math>{(x-1)} | + | From the equality, <math>\frac{1}{x-1}=\frac{2}{x-2}</math>, we get <math>{(x-1)}/times2={(x-2)}/times1</math>. |
Solving this, we get, <math>{2x-2}={x-2}</math>. | Solving this, we get, <math>{2x-2}={x-2}</math>. | ||
Thus, \ \text{only }x=0$ can satisfy the equation, {(E)}. | Thus, \ \text{only }x=0$ can satisfy the equation, {(E)}. | ||
Revision as of 22:59, 6 July 2018
Problem
The equality 
is satisfied by:
Solution
From the equality, , we get 
.
Solving this, we get, 
.
Thus, \ \text{only }x=0$ can satisfy the equation, {(E)}.
