2024 SSMO Accuracy Round Problems/Problem 6

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Problem

Three six-sided dice are rolled. Then, the product of the three numbers on the top faces in calculated. If the probability of getting the product that is not a perfect square can be expressed as $\frac{m}{n}$ where $m$ and $n$ are relatively prime positive integers, what is $m+n$?

Solution

For simplicity, we will count the number of ways of getting a product that is a perfect square. We will do casework on the number of perfect squares rolled. Firstly, there are $2^3 = 8$ ways to roll 3 perfect squares. Next, if two perfects squares rolled and the other isn't a perfect square, it is impossible for the final product to be a perfect square. If 1 perfect square is rolled, then the other two numbers rolled must be equal. There are $3$ ways to permute the rolls, $2$ perfect squares, and $4$ non-perfect squares, giving $3\cdot2\cdot4 = 24$ possibilities. Finally, if no perfect squares are rolled, we must have $236,$ giving another 6 possibilities. In conclusion, the answer is \[1-\frac{8+24+6}{6^3} = 1-\frac{19}{108} = \frac{89}{108}\implies 89+108 = \boxed{197}.\]

~SMO_Team