2005 iTest Problems/Problem 27

Revision as of 20:22, 13 October 2025 by Mathloveryeah (talk | contribs) (Solution 1)

Problem

Find the sum of all non-zero digits that can repeat at the end of a perfect square. (For example, if $811$ were a perfect square, $1$ would be one of these non-zero digits.)

Solution 1

We seek nonzero digits such that some square ends with the digit repeated. Squares modulo 4 are only 0 or 1, so 11, 22, 55, 66, and 99 are ruled out immediately (since they are 3,2,3,2,3($\mod 4$)). Out of the remaining numbers, since a square can have a last digit belonging to the set {$0,1,4,5,6,9$}, 33, 77, and 88 are ruled out as well. This leaves only 44. Our answer therefore is $\boxed{4}$.

See Also

2005 iTest (Problems, Answer Key)
Preceded by:
Problem 26
Followed by:
Problem 28
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