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1995 AHSME Problems/Problem 2

Revision as of 21:12, 8 January 2008 by Azjps (talk | contribs) (soln)
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Problem

If $\sqrt {2 + \sqrt {x}} = 3$, then $x =$

$\mathrm{(A) \ 1 } \qquad \mathrm{(B) \ \sqrt{7} } \qquad \mathrm{(C) \ 7 } \qquad \mathrm{(D) \ 49 } \qquad \mathrm{(E) \ 121 }$

Solution

$2 + \sqrt{x} = 9 \Longrightarrow \sqrt{x} = 7 \Longrightarrow x = 49 \Rightarrow \mathrm{(D)}$

See also

Template:Old AMC12 box

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