1957 AHSME Problems/Problem 39

Problem

Two men set out at the same time to walk towards each other from $M$ and $N$ , $72$ miles apart. The first man walks at the rate of $4$ mph. The second man walks $2$ miles the first hour, $2\tfrac {1}{2}$ miles the second hour, $3$ miles the third hour, and so on in arithmetic progression. Then the men will meet:

$\textbf{(A)}\ \text{in 7 hours} \qquad \textbf{(B)}\ \text{in }{8\frac {1}{4}}\text{ hours}\qquad \textbf{(C)}\ \text{nearer }{M}\text{ than }{N}\qquad\\ \textbf{(D)}\ \text{nearer }{N}\text{ than }{M}\qquad \textbf{(E)}\ \text{midway between }{M}\text{ and }{N}$

Solution

$\boxed{\textbf{(E)} \text{ midway between } M \text{ and } N}$ .

1957 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 38	Followed by Problem 40
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1957 AHSME Problems/Problem 39

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