1999 CEMC Gauss (Grade 7) Problems/Problem 7

Problem

If the numbers, $\frac{4}{5}$ , $81\%$ , and $0.801$ are arranged from smallest to largest, the correct order is

$\text{(A)}\ \frac{4}{5}, 81\%, 0.801 \qquad \text{(B)}\ 81\%, 0.801, \frac{4}{5} \qquad \text{(C)}\ 0.801, \frac{4}{5}, 81\% \qquad \text{(D)}\ 81\%, \frac{4}{5}, 0.801 \qquad \text{(E)}\ \frac{4}{5}, 0.801, 81\%$

Solution 1

We have:

$\frac{4}{5} = 0.8$

$81\% = \frac{81}{100} = 0.81$

Thus, ordering the three numbers from smallest to largest gives $\boxed {\textbf{(E)} \frac{4}{5}, 0.801, 81\%}$

Solution 2

We can also put everything in terms of thousandths, and then compare the numerators:

$\frac{4}{5} = \frac{4 * 200}{5 * 200} = \frac{800}{1000}$

$81\% = \frac{810}{1000}$

$0.801 = \frac{801}{1000}$

Thus, ordering the three numbers from smallest to largest gives $\boxed {\textbf{(E)} \frac{4}{5}, 0.801, 81\%}$

Page

Toolbox

Search

1999 CEMC Gauss (Grade 7) Problems/Problem 7

Problem

Solution 1

Solution 2