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2015 CEMC Gauss (Grade 8) Problems/Problem 1

Revision as of 22:02, 10 May 2025 by Anabel.disher (talk | contribs) (Created page with "== Problem== The value of <math>1000 + 200 - 10 + 1</math> is <math> \textbf{(A)}\ 1191 \qquad\textbf{(B)}\ 1190 \qquad\textbf{(C)}\ 1181 \qquad\textbf{(D)}\ 1209 \qquad\text...")
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Problem

The value of $1000 + 200 - 10 + 1$ is

$\textbf{(A)}\ 1191 \qquad\textbf{(B)}\ 1190 \qquad\textbf{(C)}\ 1181 \qquad\textbf{(D)}\ 1209 \qquad\textbf{(E)}\ 1211$

Solution

$1000 + 200 - 10 + 1 = 1200 - 9 = \boxed {\textbf {(A) } 1191}$

~anabel.disher

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