2009 Grade 8 CEMC Gauss Problems/Problem 16

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Problem

When it is 3:00 p.m. in Victoria, it is 6:00 p.m. in Timmins. Stefan’s flight departed at 6:00 a.m. local Victoria time and arrived at 4:00 p.m. local Timmins time. How long, in hours, was his flight?

$\text{ (A) }\ 5 \qquad\text{ (B) }\ 9 \qquad\text{ (C) }\ 13 \qquad\text{ (D) }\ 7 \qquad\text{ (E) }\ 8$

Solution 1

From the first sentence of the problem, we can realize that Timmins is $3$ hours ahead. This means that $6:00$ am in local Victoria time is the same thing as $9:00$ am in local Timmins time.

$3$ hours after $9:00$ am is $12:00$ pm, and $4$ hours after that is $4:00$ pm, so his flight was $3 + 4 = \boxed {\textbf {(D) } 7}$ hours long.

~anabel.disher

Solution 1.1

We can also use the time conversion, but convert Timmins time to Victoria time to solve the problem.

$4:00$ pm in local Timmins time would be $1:00$ pm in local Victoria time.

$6$ hours after $6:00$ am is $12:00$ pm, and $1$ hour after that $1:00$ pm, so his flight was $6 + 1 = \boxed {\textbf {(D) } 7}$ hours long.

~anabel.disher