2006 CEMC Fermat Problems/Problem 6

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Problem

The regular price for a T-shirt is $$25$ and the regular price for a pair of jeans is $$75$. If the T-shirt is sold at a $30\%$ discount and the jeans are sold at a $10\%$ discount, then the total discount is

$\text{ (A) }\ $15 \qquad\text{ (B) }\ $20 \qquad\text{ (C) }\ $30 \qquad\text{ (D) }\ $36 \qquad\text{ (E) }\ $40$

Solution

We can find each discount and then add them together.

The discount for the T-shirt would be $$25 \times 30\% = $25 \times \frac{3}{10} = $7.50$.

The discount for the T-shirt would be $$75 \times 10\% = $75 \times \frac{1}{10} = $7.50$.

Adding these, we can see that the total discount is $$7.50 + $7.50 = \boxed {\textbf {(A) } $15}$.

~anabel.disher