Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

2000 CEMC Gauss (Grade 8) Problems/Problem 3

Revision as of 15:00, 11 September 2025 by Anabel.disher (talk | contribs) (Created page with "==Problem== The value of <math>\frac{5 + 4 - 3}{5 + 4 + 3}</math> is <math> \text{ (A) }\ -1 \qquad\text{ (B) }\ \frac{1}{3} \qquad\text{ (C) }\ 2 \qquad\text{ (D) }\ \frac...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem

The value of $\frac{5 + 4 - 3}{5 + 4 + 3}$ is

$\text{ (A) }\ -1 \qquad\text{ (B) }\ \frac{1}{3} \qquad\text{ (C) }\ 2 \qquad\text{ (D) }\ \frac{1}{2} \qquad\text{ (E) }\ -\frac{1}{2}$

Solution

Evaluating the numerator and denominator, we have:

$\frac{5 + 4 - 3}{5 + 4 + 3} = \frac{9 - 3}{9 + 3} = \frac{6}{12}$

Simplifying this gives $\frac{6 \div 6}{12 \div 6} = \boxed {\textbf {(D) } \frac{1}{2}}$.

~anabel.disher

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=2000_CEMC_Gauss_(Grade_8)_Problems/Problem_3&oldid=260366"