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2000 CEMC Gauss (Grade 7) Problems/Problem 1

Revision as of 14:06, 12 September 2025 by Anabel.disher (talk | contribs) (Created page with "==Problem== The value of <math>987 + 113 - 1000</math> is <math> \text{ (A) }\ 90 \qquad\text{ (B) }\ 10 \qquad\text{ (C) }\ 110 \qquad\text{ (D) }\ 2000 \qquad\text{ (E) }...")
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Problem

The value of $987 + 113 - 1000$ is

$\text{ (A) }\ 90 \qquad\text{ (B) }\ 10 \qquad\text{ (C) }\ 110 \qquad\text{ (D) }\ 2000 \qquad\text{ (E) }\ 100$

Solution

$987 + 113 - 1000 = 1100 - 1000 = \boxed {\textbf {(E) } 100}$

~anabel.disher

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