2023 WSMO Team Round Problems/Problem 1

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Problem

Bob has a number of pencils. When Bob splits them into groups of 10, he has 3 left over. When he splits them into groups of 12, he has 5 left over. Find the smallest number of pencils Bob can have.

Solution

From the condition, possible numbers of pencils Bob could have are \[3,13,23,33,43,\boxed{53},63,\ldots\] and from the second condition we have \[5,17,29,41,\boxed{53},65,\ldots.\] So, th emsallest number of pencils Bob could have is $\boxed{53}.$

~pinkpig