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2025 CEMC Pascal Problems/Problem 2

Revision as of 14:29, 16 September 2025 by Anabel.disher (talk | contribs) (Created page with "==Problem== How many of the numbers <math>-4</math>, <math>-2</math>, <math>-3.5</math>, <math>-2.5</math>, and <math>6</math> are to the left of <math>-3</math> when placed o...")
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Problem

How many of the numbers $-4$, $-2$, $-3.5$, $-2.5$, and $6$ are to the left of $-3$ when placed on the number line?

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$\text{ (A) }\ 3 \qquad\text{ (B) }\ 2 \qquad\text{ (C) }\ 1 \qquad\text{ (D) }\ 5 \qquad\text{ (E) }\ 4$

Solution

We can simply see which numbers are less than $-3$ (since the numbers that are less than $-3$ will be to the left of $-3$), and then count to see how many numbers satisfy the condition.

$-4 < -3$

$-2 > -3$

$-3.5 < -3$

$-2.5 > -3$

$6 > 3$

Of these numbers, $\boxed {\textbf {(B) } 2}$ of them would be to the left of $-3$.

~anabel.disher

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