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2010 CEMC Gauss (Grade 8) Problems/Problem 1

Revision as of 19:40, 30 September 2025 by Anabel.disher (talk | contribs) (Created page with "==Problem== <math>2 + 3 \times 4 + 10</math> equals <math> \text{ (A) }\ 24 \qquad\text{ (B) }\ 60 \qquad\text{ (C) }\ 70 \qquad\text{ (D) }\ 19 \qquad\text{ (E) }\ 34 </math...")
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Problem

$2 + 3 \times 4 + 10$ equals

$\text{ (A) }\ 24 \qquad\text{ (B) }\ 60 \qquad\text{ (C) }\ 70 \qquad\text{ (D) }\ 19 \qquad\text{ (E) }\ 34$

Solution

Following order of operations, we have:

$2 + 3 \times 4 + 10 = 2 + 12 + 10$

$=14 + 10 = \boxed {\textbf {(A) } 24}$

~anabel.disher

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