2005 iTest Problems/Problem 28

Revision as of 20:36, 13 October 2025 by Mathloveryeah (talk | contribs) (Created page with "==Problem== Yoknapatawpha County has <math>500,000</math> families. Each family is expected to continue to have children until it has a girl, at which point each family stops...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem

Yoknapatawpha County has $500,000$ families. Each family is expected to continue to have children until it has a girl, at which point each family stops having children. If the probability of having a boy is $50\%$, and no families have either fertility problems or multiple children per birthing, how many families are expected to have at least $5$ children?

Solution 1

The probability of having at least 5 children is the same as having the first 4 children be boys. The probability of 4 boys in a row is $(\frac{1}{2})^4=\frac{1}{16}$. To find the expected number of families with at least 5 children, we multiply this probability by the number of families. Thus, our answer is $\frac{500000}{16}=\boxed{31250}$.

See Also

2005 iTest (Problems, Answer Key)
Preceded by:
Problem 27
Followed by:
Problem 29
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 TB1 TB2 TB3 TB4