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2012 CEMC Gauss (Grade 8) Problems/Problem 6

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Problem

Ronald buys a pizza cut into 12 equal parts. He then cuts each part into 2 equal pieces. If he eats 3 of these pieces, what fraction of the pizza does he eat?

$\text{ (A) }\  \frac{1}{24} \qquad\text{ (B) }\ \frac{1}{2} \qquad\text{ (C) }\ \frac{3}{8} \qquad\text{ (D) }\ \frac{1}{6} \qquad\text{ (E) }\ \frac{1}{8}$

Solution

When Ronald cuts each part into 2 equal pieces, he now has $12 \times 2 = 24$ equal pieces.

The fraction of the pizza that he eats would then be $\frac{3}{24} = \frac{3 \div 3}{24 \div 3} = \boxed {\textbf {(E) } \frac{1}{8}}$.

~anabel.disher and whoever her friend was

2012 CEMC Gauss (Grade 8) (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
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CEMC Gauss (Grade 8)