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2013 USAJMO Problems/Problem 6

Revision as of 10:40, 14 April 2014 by Suli (talk | contribs) (Created page with "==Solution== Without loss of generality, let x < y < z. Then <math>\sqrt{x + xyz} = \sqrt{x - 1} + \sqrt{y - 1} + \sqrt{z - 1}</math>.")
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Solution

Without loss of generality, let x < y < z. Then $\sqrt{x + xyz} = \sqrt{x - 1} + \sqrt{y - 1} + \sqrt{z - 1}$.

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