1989 AJHSME Problems/Problem 6

Problem

If the markings on the number line are equally spaced, what is the number $\text{y}$ ?

$[asy] draw((-4,0)--(26,0),Arrows); for(int a=0; a<6; ++a) { draw((4a,-1)--(4a,1)); } label("0",(0,-1),S); label("20",(20,-1),S); label("y",(12,-1),S); [/asy]$

$\text{(A)}\ 3 \qquad \text{(B)}\ 10 \qquad \text{(C)}\ 12 \qquad \text{(D)}\ 15 \qquad \text{(E)}\ 16$

Solution

Five steps are taken to get from $0$ to $20$ . Each step is of equal size, so each step is $4$ . Three steps are taken from $0$ to $y$ , so $y=3\times 4=12\rightarrow \boxed{\text{C}}$ .

There are five steps, and y is step number three. We can get our answer by multiplying since all the steps are the same. $20\cdot \frac{3}{5}=12$ . So, our answer is $\boxed{\text{C}}$ ----stjwyl

1989 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 5	Followed by Problem 7
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All AJHSME/AMC 8 Problems and Solutions

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1989 AJHSME Problems/Problem 6

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