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1998 CEMC Pascal Problems/Problem 4

Problem

The value of $(\sqrt{169} - \sqrt{25})^2$ is

$\text{ (A) }\ 64 \qquad\text{ (B) }\ 8 \qquad\text{ (C) }\ 16 \qquad\text{ (D) }\ 144 \qquad\text{ (E) }\ 12$

Solution

We can simply evaluate the square roots to figure out the value of the expression:

$(\sqrt{169} - \sqrt{25})^2 = (13 - 5)^2 = 8^2 = 64$

~anabel.disher

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