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1999 CEMC Pascal Problems/Problem 1

Problem

The value of $\frac{4 \times 4 + 4}{2 \times 2 - 2}$ is

$\text{ (A) }\ 2 \qquad\text{ (B) }\ 6 \qquad\text{ (C) }\ 10 \qquad\text{ (D) }\ 12 \qquad\text{ (E) }\ 18$

Solution

$\frac{4 \times 4 + 4}{2 \times 2 - 2} = \frac{16 + 4}{4 - 2} = \frac{20}{2} = 10$

~anabel.disher

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