1999 CEMC Pascal Problems/Problem 10

Problem

$10 + 10^{3}$ equals

$\text{ (A) }\ 2.0 \times 10^{3} \qquad\text{ (B) }\ 8.0 \times 10^{3} \qquad\text{ (C) }\ 4.0 \times 10^{1} \qquad\text{ (D) }\ 1.0 \times 10^{4} \qquad\text{ (E) }\ 1.01 \times 10^{3}$

Solution

Using order of operations, we have:

$10 + 10^{3} = 10 + 1000 = 1010$

Converting this into scientific notation, like the answer choices have, we get:

$1010 = \boxed {\textbf {(E) } 1.01 \times 10^{3}}$

~anabel.disher

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1999 CEMC Pascal Problems/Problem 10

Problem

Solution